(2014? Chenzhou Second Mold) As shown in the figure, the bottom surface of the four-sided pyramid P-ABCD is a right-angled trapezoid, BA⊥AD, CD⊥AD, CD=2AB, PA⊥bottom ABCD, E is PC

Solution (1) Prove: Take the midpoint Q of PD and connect EQ and AQ, then QE=12CD=AB... (1 point)

QE∥CDCD∥ABQE=AB? QE∥..AB…(2 points)?Is the quadrilateral ABEQ a parallelogram?BE∥AQ…(3 points)

BE∥AQAQ?Plane PADBE?Plane PAD?BE∥Plane PAD…(5 points) )

(2) Prove: PA⊥Plane ABCDCD?Plane ABCD?PA⊥CD,

And ∵CD⊥AD, PA∩AD=A

∴CD⊥Plane PAD

And ∵AQ?Plane PAD

∴AQ⊥CD,

And ∵PA=AD, Q is the midpoint of PD

∴AQ⊥PD,

And∵PD∩CD=D

?AQ⊥Plane PCDBE∥AQ has been liked and disliked Your answer to this question What's the rating? Comments are closed // High quality or satisfactory or special type or recommended answer time window.iPerformance window.iPerformance.mark('c_best', new Date); Recommended lawyer service: If your problem is not solved, please describe your problem in detail For questions, get free professional consultation through Baidu Lulin and other similar questions 2022-09-08 As shown in the figure, in the four-sided pyramid P-ABCD, PA is the vertical plane ABCD, the base ABCD is a right-angled trapezoid, and the angle ABC = angle BAD = 90 degrees E is AB2012-04-0211． As shown in the figure, in the square pyramid P-ABCD, PA⊥ plane ABCD, the base ABCD is a right-angled trapezoid, ∠ABC =∠BAD=90°, AD>BC, 42010-10-03 As shown in the figure, the bottom surface of the square pyramid P-ABCD is Right-angled trapezoid, BA⊥AD, CD⊥AD, CD=2AB, PA⊥base ABCD, E is the midpoint of PC, PA=AD=AB=11942010-08-18 Known: In the square pyramid P-ABCD, PA The vertical plane ABCD, the base ABCD is a right-angled trapezoid, where ∠A=90°, AB is parallel to CD, CD=2AB, 52011-06-12 As shown in the figure, in the square pyramid P-ABCD, the PA⊥ plane ABCD, the base ABCD is a right angle Trapezoidal, ∠ADC is a right angle, AD‖BC, AB⊥AC, AC=AB=2, G is the 52011-12-13 of △ABC. As shown in the figure, the base of the four-sided pyramid P-ABCD is a right-angled trapezoid, AB|| CD and AB vertical plane PAD AB=2DC, side 132013-04-037. As shown in the figure, in the quadrangular pyramid P-ABCD, the base ABCD is a rectangle, the side edge PA is perpendicular to the base ABCD, E and F are AB and PC respectively. midpoint. 192013-01-12 As shown in the figure, the base of the quadrangular pyramid P-ABCD is a right-angled trapezoid, PA⊥The base ABCD, AB⊥AD, CD⊥AD, CD=2AB, E is the midpoint of PC, PA=AD=AB =1.

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