What are the answers to 15 abnormal Google interview questions?

The twelve questions are the physics questions of the last semester of Grade Three, about the balance!

the answer is: put three of the eight coins on the left disk, put the other three on the right disk, and leave the other two aside. If the two disks are equally heavy, the heavy coins are among the remaining two coins, and then weigh them, ok. If one disk is heavier, put three coins on this disk, one on the left disk and the other on the right disk, and then measure again. If it is equal, then The heavy coins are on the heavier plate.

The fifth question is about mathematical geometry, which is probably touched in the third day of the second grade. You should know that the manhole cover is on the road, and something must hold it on the edge of the manhole cover, so that the manhole cover will not fall, and the edge is very small. If the manhole cover is round, the radius is equal. If the manhole cover is placed sideways for some reason, it will not fall because the diameter is longer than the edge. If As soon as he hits the side, he will fall, because the rectangle is composed of two right-angled triangles, and the hypotenuse of the right-angled triangle is longer. If you say this, the equilateral triangle should be ok, and some irregular figures can also be, and there may be an aesthetic factor, or the manhole cover author first thought of the round manhole cover, and then the whole world rounded the manhole cover, so no one cares about why the equilateral triangle manhole cover is not needed ... Because of the limited knowledge, At that time, I asked the teacher why I couldn't use an equilateral triangle, but the teacher didn't answer me. I'm sorry I can't prove it to you.

Question 7, first of all, think about it. Every second, the minute hand is turning, so will the hour hand and minute hand overlap again the next second when they overlap? Think deeper, I think we should consider the degree of the circle. Through calculation, we know that the minute hand goes 6 degrees every minute, while the hour hand goes .5 degrees. Then, if it is twelve o'clock, the hour hand points to "12", and it coincides once, but every second, the minute hand rotates subtly, and so does the hour hand. (Personally, I think that I am only a junior three student, which may not be the correct answer). I think that 24 hours a day is naturally 24 times.

The eleventh question belongs to reasoning, and I don't know (hehe), but there is a similar question on the Internet: pirates divide gold coins. There are five pirates. The first one starts to divide gold coins, and if his distribution method is not agreed by half, he will be executed and let the next one.

Assuming that every pirate is extremely intelligent and rational, they can make strict logical reasoning and judge their own gains and losses rationally, that is, they can get the most gold coins on the premise of saving their lives. At the same time, assuming that the results of each round of voting can be implemented smoothly, what kind of distribution scheme should the pirates who draw No.1 put forward so that they can not be thrown into the sea and get more gold coins?

The accepted standard answer to this question is: Pirate No.1 gives 1 gold coin on No.3, 2 gold coins on No.4 or No.5, and he gets 97 gold coins alone, that is, the distribution scheme is (97,,1,2,) or (97,,1,,2). Now let's look at the following rational analysis:

Let's start with Pirate No.5, because he is the safest and there is no risk of being thrown into the sea, so his strategy is also the simplest, that is, if all the people in front are dead, then he can get the 1 gold coins alone.

Next, look at No.4, and his chances of survival depend entirely on the existence of others in front, because if all the pirates from No.1 to No.3 feed sharks, then no matter what distribution scheme No.4 proposes, No.5 will definitely vote against it to let No.4 feed sharks to keep all the gold coins. Even if No.4 curry favor with No.5 to save his life and put forward a plan of (,1) to let No.5 monopolize the gold coins, No.5 may feel that it is dangerous to keep No.4 and vote against it so that it can be fed to sharks. Therefore, rational No.4 should not take such a risk and pin his hope of survival on the random selection of No.5. Only by supporting No.3 can he absolutely guarantee his own life.

Let's look at No.3 again. After the above logical reasoning, he will put forward such a distribution scheme as (1,,), because he knows that No.4 will unconditionally support him and vote for it, so adding his own vote will make him secure the 1 gold coins.

However, No.2 also knows the allocation scheme of No.3 through reasoning, so he will put forward the scheme of (98,,1,1). Because this scheme is relative to the distribution scheme of No.3, No.4 and No.5 can get at least one gold coin, rational No.4 and No.5 will naturally think that this scheme is more beneficial to them and support No.2, and they don't want No.2 to go out and No.3 will distribute it. In this way, No.2 can take 98 gold coins with a fart.

Unfortunately, Pirate No.1 is not a fuel-efficient lamp, and after some reasoning, he also understands the allocation scheme of Pirate No.2.. The strategy he will take is to give up No.2, give No.3 a gold coin, and give No.4 or No.5 two gold coins at the same time, that is, put forward the distribution scheme of (97,,1,2,) or (97,,1,,2). Because the distribution scheme of No.1 can get more benefits for No.3, No.4 or No.5 than that of No.2, then they will vote for No.1, and with No.1' s own vote, 97 gold coins can easily fall into No.1' s pocket. But google's question has no clear conditions, only that if you don't get consent, you will die, and nothing else. What will you do if the crew let you die regardless of the willy-nilly? Maybe this question doesn't need logical analysis, but from the perspective of social reality, such as fawning on good acquaintances.

I seem to have read the tenth question in a book, but I didn't write the answer. I think so. Since he can't write it on paper if he doesn't know the number, he can only confirm it with his mobile phone: ask Bob to call my mobile phone number.

I have come up with many answers to the fifteenth question. There are countless answers to this kind of brain teaser, but the questioner only looks at the correct answer in his hand, so I'll give you my most thunderous one for reference: if it's only as small as a coin, the stirrer is generally in the shape of a quadrilateral pentagon when viewed from the plane, and the stirring blade is round when it rotates, so why not just stand at the position where the stirring blade can't cut your dead corner?

the third question, biological explanation, is that the ratio of boys to girls is 1: 1, because the probability question is only a rough estimate, and there is no accurate answer. The examinees just want to look at your problem-solving ideas. This is how I interpret it: since it is a one-to-one ratio, it means either a man or a woman. Because it is a rough estimate, it is considered that there is a man and a woman every two births (it is impossible in reality), that is, if it is a man or a woman, it is not. Think of him as only these two situations, and the probability is one to one, that is, two men and one woman, so the ratio is two to one. < P > Question 8, I won't, but there are netizens' opinions on the Internet: for a software engineer, it is necessary to try to avoid "dead beef" in the software. Not only is it not good for the software itself, but it will also bring damage to the whole software. Dead beef is not only inedible, but also attracts many pests such as warehouse flies.

Most of the other questions are subjective, and there is no absolute answer. The questioner just wants to see your thoughts. But I have told you everything I can. It is useless to just look at the answers. The key is analysis. I hope I have spent an hour on a long speech to help you.