A factory wants to recruit 150 workers from two middle schools in A and B.

Because the number of people in B is not less than twice that of A, then the number of people in B is twice that of A, so the number of people in B should be150/(1+2) * 2 =100, and the number of people in A is 50. At this time, the monthly salary should be:

50 * 600+100 *1000 =130000 =13 (ten thousand yuan)

Anyway, the number of people in B can't be less than 100, because in that case, B can't be twice that of A. So if the number of people in B is1kloc-0/,the number of people in A is 49, and the monthly salary payable at this time is:

49*600+ 10 1* 1000= 130400

So according to the meaning of the question, the number of people in type A should be 50.

Suppose there are workers who recruit a type of work and workers who recruit b type of work, then the meaning of the question will be known:

a+b= 150 ( 1)

b & gt=2a (2)

Known (1)

a+b= 150

a= 150-b

From (2):

b & gt=2a

b & gt=2*( 150-b)

b & gt=300-2*b

b+2 * b & gt； =300

3 * b & gt=300

b & gt= 100

And the monthly salary = 600 * a+1000 * b.

=600*a+600*b+400*b

=600*(a+b)+400*b

According to (1), a+b= 150.

=600* 150+400*b

So the smaller b is, the better, so b= 100.

a=50。

Monthly salary = 600 * 50+1000 *100 =130000.