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Extend the extension line of AF AC DC to m, and δABF is all equal to δCMF, so AB=CM=CD.

Through AE=EB

BF=FC

△AED region = 15

EG=ED/5

△AEG= 15× 1/5=3

△ABF area = 15

FH=AH/3

△BFH= 15/3=5

Quadrilateral BHGE= 15-3-5=7