Shenyang play element recruitment

The six elements A, B, C, D, E and F with increasing atomic numbers are located in the first four periods of the periodic table. If the energy series of element A is equal to the number of electrons outside the nucleus, then element A is H; Element b contains three energy levels, each of which contains the same number of electrons. If the electron configuration outside the nucleus is 1s22s22p2, then element B is element C; If there are 8 electrons with different motion states outside the nucleus of D, then D is O; If the atomic number of c is between carbon and oxygen, then c is an element of n; The adjacent families of element E and element F have the same period, and their atomic numbers differ by 3, so they should belong to the eighth and adjacent families. The ground state atom of element E has four unpaired electrons, and the peripheral electronic configuration is 3d64s2, so E is Fe, so F is Cu.

The electronegativity of (1) element increases with the increase of atomic number in the same period, so the electronegativity c < n < o,

Therefore, the answer is: c < n < o；;

(2) The particle formed by N and O according to the atomic number ratio 1: 3 is NO3-, and the valence electron logarithm of N is 3+5+ 1? 2×32=3, there is no lone electron pair, so its spatial configuration is a plane triangle.

So the answer is: plane triangle;

(3) The radius of Fe2+ion is larger than that of Fe3+ ion, with less charge, so the lattice energy of FeO is smaller than that of Fe2O3, and the melting point of FeO is lower than that of Fe2O3.

So, the answer is: low; The radius of Fe2+ ion is larger than that of Fe3+ ion, and its charge is less, so the lattice energy of FeO is smaller than that of Fe2O3.

(4) The number of C atoms in the cell =4+6× 12+8× 18=8, and the cell mass =8× 12NAg=96NAg. If the crystal density is ρg/cm3, then

Unit cell volume = 96 nag rho? G/cm3=96ρNAcm3, then the cell side length =396ρNAcm, and the C atom and four surrounding C atoms form a regular tetrahedron, and the side length of this regular tetrahedron =396ρNAcm×22=2×.