Job Recruitment Website - Job information - (20 1 1? Changsha) As shown in the figure, the power supply voltage is constant at 4V, and the fixed resistance R 1=40? ，R2=20？ , the switch is closed, the ammeter reading is _ _ _ _ _ A.
(20 1 1? Changsha) As shown in the figure, the power supply voltage is constant at 4V, and the fixed resistance R 1=40? ，R2=20？ , the switch is closed, the ammeter reading is _ _ _ _ _ A.
As can be seen from the figure, R 1 and R2 are connected in parallel, and U=U 1=U2=4V, and the ammeter measures the main current.
I 1 = ur 1 = 4v 40ω= 0. 1A，I2 = UR2 = 4V20Ω = 0.2A，I = I 1+I2 = 0. 1A+0.2A = 0.3a。
Q=I2Rt=UIt=4V×0.3A×5×60S=360J。
So the answer is: 0.3,360.
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