Job Recruitment Website - Zhaopincom - An engineering team wants to recruit workers A and B 150, and the monthly wages of A and B are 600 yuan and 1000 yuan respectively. The number of workers in B is needed now.
An engineering team wants to recruit workers A and B 150, and the monthly wages of A and B are 600 yuan and 1000 yuan respectively. The number of workers in B is needed now.
Suppose there are x workers in a job and (150-x) workers in a job.
150-x≥2x solution: x≤50, that is, 0≤x≤50(2 points).
Assuming that the monthly salary is Y yuan, then
y=600x+ 1000( 150-x)
=-400x+ 150000(4 points)
∵-400 < 0, ∴y decreases with the increase of X.
And when ∵0≤x≤50 and x=50, ∴y minimum value =-400× 50+150000 =130000 (yuan).
∴150-x =150-50 =100 (person)
A: When A and B recruit 50 100 people respectively, the monthly salary can reach at least130,000 yuan.
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