In a parallelogram, if the bisectors of AB = 3, BC = 4, ∠ A and ∠ D intersect BC at E and F respectively, then EF=?

E is EE' parallel to AB, and AD is e'. Triangle ABE is equal to AE'E, so AB.

Equal to AE', connecting BE' and AE intersect at O, isosceles triangle ABE', and AO is both the bisector and the height, so AO is perpendicular to BE', and the diagonals of parallelogram Abe' are perpendicular to each other, so it is a diamond, so BE is equal to AB, which is equal to 3, so E'D is equal to 1.

The quadrilateral BFDE' BEcause the angle BE'A is equal to the angle FDA, be' is parallel to DF, so BF equals E'D equals 1. So EF equals 2.