Shenyang container recruitment

As can be seen from the figure, the bottom area of the container s a < s b,

∫v = sh, the liquid level is flat, and H is the same.

∴v a < v b，

∑ρ= mV，m a > m b，

∴ density relation of two liquids: ρ a > ρ b;

From M A > M B, that is, ρ A V A > ρ B V B? ρ a s a h > ρ b s b h, we can get:

ρA S A >ρB S B；

If the liquid level is still flat after adding the stock solution to the two containers respectively, then:

① ρ A S A h' > ρ B S B H', that is, m a' > m b.

From G=mg, it can be concluded that G A > G B；;

Also, for a cylindrical container, the pressure of the liquid at the bottom of the container is f = PS = rhoghs = rhogv = mg = g,

∴ pressure of liquid at the bottom of each container: fa > FB.

②∫p =ρGH, the liquid level remains flat (H is the same), ρ A > ρ B,

∴ pressure of liquid at the bottom of each container: pa > pb.

So choose D.