Job Recruitment Website - Job seeking and recruitment - The head of the pump is increased by 2 meters, and other parameters are unchanged, so how much is its power increased, online and so on! !
The head of the pump is increased by 2 meters, and other parameters are unchanged, so how much is its power increased, online and so on! !
Power = flow × lift, incremental power = flow × incremental lift. Known flow = =160m 3/h/h, and the increased lift is 2m.
160 (m3/hour) water is: 160 (ton/hour) water.
160(t/h)= 160× 10^3(kg)/3600(s)= 160× 10^3×g/3600(n/s)
∴ increased power =160×103× g/3600 (n/s )× 2 (m) = 871.70 (n m/s) = 0.872kw.
Where g is the acceleration of gravity, and g = 9.80665 (m/s 2).
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