Chibi electronic recruitment

A, B, C and D are short-period elements, and the valence electron configuration of element A is ns2np2, so element A belongs to the IVA family.

The number of atoms in the outermost layer of element B is 3 times of the number of layers of electrons. If the number of electrons in the outermost layer does not exceed 8, then element B is O;

If there are three unpaired electrons in the p energy level of the M energy layer of the atom of element C, then element C is element P;

There are only two pairs of electrons in the M energy layer outside the nucleus of element D, so element D is element S;

(1) When n=2, A is element C, and the molecular structure of CO2 is symmetrical, and its positive and negative charge centers of gravity coincide, so it is a nonpolar molecule; The simple molecular structure of CH2O is HCHO, and C atom contains three δ bonds and 1 π bonds, so the valence shell electron logarithm of C atom is 3, so C atom is hybridized by sp2, so the answer is: nonpolar; sp23; 1;

(2) When n=3, A is Si element, and the crystal formed by A and B is SiO2, which belongs to atomic crystal. There are covalent bonds between Si atoms and O atoms in silica crystals, so the answer is: covalent bonds;

(3) If n=3, A is an element of Si, and the first ionization energy of this element increases with the increase of atomic number, but the first ionization energy of IIA and VA elements is greater than that of their neighboring elements, so the order of the first ionization energy is p > s > si.

The valence electron logarithm of S atom in SO2 molecule =2+ 12×(6-2×2)=3, and it contains a lone electron pair, so the VSEPR model of SO2 is triangular, and its spatial configuration is V-shaped, so the answer is: P > S > Si triangle; V shape;

(4) Copper ions contain empty orbitals, and O atoms in water molecules contain lone electron pairs to form coordination bonds, which point from the atoms providing lone electron pairs to the atoms providing empty orbitals, so its representation is as follows:

So the answer is: