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Employment strategy
Some specific calculation methods can be illustrated by examples: a company needs to hire an employee for a certain position, and Wang and Zhou took five rounds of exams. The scores of each round of exams and the weight system of each round of exams are as follows: The first round of exams:
The second round of political and ideological examination:
The third round of professional skills examination:
The fourth round of foreign language examination:
The fifth round of computer operation examination:
Psychological quality: Wang scored 90 80 60 90 70 weeks, 70 90 80 70 80 weight coefficient 65 438+0 0.6 65 438+0 0.8 weight coefficient 20.50.665 438+0.65 438+0.000.7 If the weights of all rounds are the same, Wang scored 90+80+60. Weekly total score: 70+90+80+70+80=390. Because only one person is hired, it is impossible to decide who to hire under this weight system. If the position to be recruited pays more attention to the second and fourth examination items (that is, the weight is higher), then Wang's total score is: 90 * 0.6+80 *1+60 * 0.5+90 *1+70 * 0.8 = 310; The total score of the week is: 70 * 0.6+90 *1+80 * 0.5+70 *1+80 * 0.8 = 306. Obviously, Wang should admit. If the position to be recruited pays more attention to the third and fourth rounds of examinations, then Wang's part is: 90 * 0.5+80 * 0.6+60 *1+90 *1+70 * 0.7 = 292; The total score of the week is: 70 * 0.5+90 * 0.6+80 *1+70 *1+80 * 0.7 = 295. Obviously, Zhou should admit it. The former total score recruitment method is more suitable for many candidates to apply for the same position. If many people apply for multiple positions at the same time, enterprises can adopt the following multi-position recruitment strategies in order to hire suitable candidates for each position. This method can be illustrated by an example: a company wants to hire three out of six candidates. The comprehensive scores of six candidates in three positions are as follows: candidate 1, candidate 2, candidate 3, candidate 4, candidate 5, candidate 6, minimum requirement position A 390 370 320 325 300 380 360, position B 385 360 355 330 325 360 350. C 386 345 370 360 160 350 340 Therefore, there are many ways to select three candidates from the above six candidates for three different positions, but the following methods are more practical: one with the highest score in each position (comparison between candidates-horizontal comparison) and one with the highest score in each position examination (comparison of individual scores of candidates in different positions-vertical comparison) Among the six candidates, candidate 1 scored the highest in position A (390 points), and candidate 1 also scored the highest in position A in three position examinations, so it is most appropriate to choose candidate 1 as position A; The candidate with the highest comprehensive score in position B is still 1, but he has been placed in position A, so candidate 2 or candidate 6 is the suitable candidate. The person with the highest comprehensive score in position C is candidate No.3 except candidate 1, so position C accepts candidate No.3..
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