Recruitment examination plan

Remember that the events passed by the applicant in the three designated courses are A, B and C respectively.

P(A)=0.5，P(B)=0.6，P (c) = 0.9。 -(2 points).

(Ⅰ)? Option 1: the probability of candidates passing the exam

p 1 =P(A？ b？ . C )+P(。 Answer? b？ C)+P(A？ . b？ C)+P(A？ b？ c)

=0.5×0.6×0. 1+0.5×0.6×0.9+0.5×0.4×0.9+0.5×0.6×0.9

=0.03+0.27+0. 18+0.27

= 0.75.- (7 points)

(Ⅱ)? The probability of candidates passing the scheme 2 exam

P ^ 2 = 1 ^ 3p(A？ B)+ 1 3 P(B？ C)+ 1 3 P(A？ c)

= 1 3 ×(0.5×0.6+0.6×0.9+0.5×0.9)

= 1 3 × 1.29

= 0.43-(12 points)