Find the cost calculation formula of each process of electric wire. thank you

Single branch: W=π×d2/4×ρ(kg/km)

Torsion: W=π×d2/4×λ×N×ρ(kg/km)

Direct amplifier: W=π×d2/4×N×ρ(kg/km)

π: pi

D: conductor diameter (mm)

N: number of conductors

λ: torsional coefficient λ= 1+(π*d 1/H)?

Twist coefficient of different kinds of steel wire;

1. Torsion coefficient of common A/V line: λ= 1.02.

2. Torsion coefficient of horn line: λ= 1+(π*d 1/H)2,

λ 1= 1.05; λ2= 1.02; λ= 1.02 has only one twist.

3. The twist coefficient of 3.UL wire and other wires: λ= 1.025 (the twist pitch is designed to be 20 times of D 1).

Where: h is the unit of stranded pitch: mm, and d 1 is the unit of stranded base circle diameter: mm.

ρ: conductor density

2, the dosage of the bag

Longitudinal packaging: W= width× thickness× ρ (kg/km)

Packing: W= width× thickness× ρ×1.5 (kg/km)

ρ: band density

D2: stranded outer diameter: the stranded outer diameter of each common stranded wire D2=M*D 1.

The value of m is the twist multiple.

D 1 is the diameter of a single insulated wire. (Unit: mm)

3, the amount of knitting materials

Woven dosage: W=(π×d? /4×Sinα)×2×8×N×ρ(kg/km)

α=ATAN{L/[π*(D 1+2*d)]}

(Example) Weaving Calculation

No.5 woven net

Number of half spindles 8

Weaving spacing: 40.64

Weaving angle: 70.0

Outer diameter before weaving: 5.5

Knitting coefficient: 0.58

Braided conductor diameter: 0. 12

Knitting density r: 82.6%

Number of parallel lines: 10

Knitting dosage: 17+09

α: weaving angle

L: weaving spacing

D 1: knitting front outer warp

D: diameter of braided conductor

N: number of parallel conductors

ρ: density of braided conductor

R: weaving density

4. Dosage of shielded cored wire

Single-core winding dosage: W=π×d? /4×λ×N×ρ (kg/km)

λ: wrapping coefficient λ=[ 1+(π*D2/H)? ] 0.5 The winding pitch h is generally a fixed value of 24 mm.

D2: Diameter of base circle behind D2 =D 1+d*2 Unit: mm.

Multi-core winding dosage: W=π×D? /4×λ×N×ρ (kg/km)

λ: wrapping coefficient λ=[ 1+(π*D? /H)？ ] 0.5 The winding pitch h is generally a fixed value of 24 mm.

D2: diameter of base circle after winding D2=D 1*M+d*2 unit: mm(M is the stranded multiple of core wire, see table 1- 1).

D: Diameter of wrapped conductor: mm..

D 1: insulation outer diameter of single-core conductor, in millimeters.

Calculation of shielding ratio of single core winding

Insulated wire diameter: 1. 1 pitch: 24

Winding diameter: 0. 12 winding number: 30

Winding angle: 0.9875 One-way shielding ratio P: 0.951164188.

Calculation of shielding ratio of double-core common winding

Single core diameter: 1.25 pitch: 24

Winding diameter: 0. 12 winding number: 48

Winding angle: 0.96208 Unidirectional shielding ratio P: 0.438+035.

5, steel strand calculation:

λ: core-like twisted pair of data cable λ= 1.025.

Wiring coefficient λ= 1.02

H: stranded wire spacing: H=M*D 1*20 unit: mm.

D2: twisted base circle diameter D2=D 1*M unit: mm.

M: twist multiple of core wire (see table 1- 1)

D 1: insulation outer diameter of single-core conductor, in mm.

(Table 1- 1)

Core number (pair) twist multiple m, core void area coefficient and external void area coefficient

12C20 1.57 1

23C2. 1540.04 1.248

34c 2.4 140.2 15 1.22

45C2.70.543 1.259

56C3 1.025 1.329

67C30 1.329

79C3.70 1.679

820C5. 1540 1.944

6, the amount of heat preservation materials

1)PVC material w = π (d12–d12)/4× ρ (kg/km).

2) batching

PP: EVA: color masterbatch = 14: 1: 0.04.

PP dosage: w = π (d12–d12)/4× ρ×1400/1504 (kg/km).

EVA dosage: w = π (d12–d12)/4×ρ×100/1504 (kg/km).

Masterbatch dosage: w = π (d12–d12)/4× ρ× 4/1504 (kg/km).

PP: color masterbatch = 10: 0.026

PP dosage: w = π (d12–d12)/4×ρ×10000/10026 (kg/km).

Masterbatch dosage: w = π (d12–d12)/4× ρ× 26/10026 (kg/km).

LDPE:HDPE: masterbatch = 3: 1: 0.06.

LDPE dosage: w = π (d12–d12)/4× ρ× 300/406 (kg/km).

HDPE dosage: w = π (d12–d12)/4× ρ×100/406 (kg/km).

Masterbatch dosage: w = π (d12–d12)/4× ρ× 6/406 (kg/km).

Low density polyethylene (short for low-density polyethylene)

LDPE dosage: w = π (d12–d12)/4× ρ (kg/km).

LDPE: PP: masterbatch = 7: 1: 0.03.

LDPE dosage: w = π (d12–d12)/4× ρ× 700/803 (kg/km).

PP dosage: w = π (d12–d12)/4× ρ×100/803 (kg/km).

Masterbatch dosage: w = π (d12–d12)/4× ρ× 3/803 (kg/km).

LDPE:HDPE: nucleating agent: masterbatch = 3: 1: 0.02: 0.06.

LDPE dosage: w = π (d12–d12)/4×ρ× (1-foaming degree )× 300/408 (kg/km).

HDPE dosage: w = π (d12–d12)/4×ρ× (1-foaming degree) × 100/408 (kg/km).

Dosage of nucleating agent: w = π (d12–d12)/4×ρ× (1-foaming degree )× 2/408 (kg/km).

Masterbatch dosage: w = π (d12–d12)/4×ρ× (1-foaming degree) × 6/408 (kg/km).

Foaming degree: 0.35% (suitable for general wire)

D 1: insulation outer diameter of core wire

D 1: stranded outer diameter of conductor d1= ((4 * n-1)/3) 0.5 * d, where: n is the number of conductors and d is the diameter of conductors.

Rho: density

7. Calculation of external quilt consumption:

1) loop

① Single winding round wire (as shown in figure1): w = π (d2-(d1+d) 2)/4× ρ (kg/km).

② Round line of two-branch winding (as shown in Figure 2): w = π (D2-(d1+2d) 2)/4× ρ+d1* (d1+2d) * ρ (kg/km).

③ Round line with ground wire (as shown in Figure 3): w = π (D2-(d1* n) 2-d12)/4× ρ (kg/km).

④ Braided thread (Figure 4): w = π (d2-(d1+2 * d+2 * d3) 2)/4× ρ (kg/km).

⑤ Calculation of twist of regular multi-core wire:

Three cores: w = (π (D2-(d1* 2.154) 2/4+1.248d1) × ρ (kg/km).

Four cores: w = (π (D2-(d1* 2.414) 2/4+1.22d1) × ρ (kg/km).

Five cores: w = (π (D2-(d1* 2.7) 2/4+1.259d1) × ρ (kg/km).

Six/seven/eight cores: w = (π (D2-(d1* 3) 2/4+1.329d1) × ρ (kg/km).

⑥ Irregular complex compound line: W=πD2/4×ρ-∑ (the area of all circles )×ρ-void area×ρ (kg/km).

(I'm not sure, please ask the engineer to evaluate)

These include:

D: outer cover wire diameter D 1: insulated wire diameter d is shielded conductor diameter d3 is aluminum foil thickness.

ρ: density of coating material

2) Flat shape (as shown in Figure 5)

w =(B2×π/4×ρ+a×b×ρ)-2(d 12×π/4×ρ)(kg/km)

3) Square horn line (as shown in Figure 2)

Number of outer quilts of circular parts

7 Stranded conductor: w = (π (D2-(d1* 3) 2/4+1.329d1) × ρ;

The external coating amount of the square part = the side length of the square is 2×ρ- the stranded outer diameter of the conductor is 2×π/4×ρ.

Amount of outer cover for intermediate conjoined part = thickness of connecting part (0.2) area × ρ

The total amount of external quilts ∑ = the amount of external quilts in the circular part+the amount of external quilts in the square part+

The outer cover of the intermediate conjoined part

Red injection dose = {total conjoined thickness area (1.5)- thickness area of connecting part (0.2)} × ρ

Figure 2

4) Ellipse (as shown in Figure 3)

W=π×a×b×ρ (kg/km)

A and b represent half of the minor axis and the major axis, respectively.

Rho is the density of the coating compound.

5) Implement air traffic control

W=π×D×H×ρ(kg/km) Figure 3

D: the diameter of the outer quilt

H: the average thickness of the shell.

ρ: density of outer layer material

8, nylon rope (polyester fiber) dosage calculation:

Fiber dosage = fiber denier /9000× number of shares (kg/km)

9. Specific gravity of common conductors, insulating materials and cladding materials (ρ: g/cm3).

8.9 BC

Arvo: 2.70.

SPC: 9.0

TC: 8.9

CCS: 8.0

Copper clad aluminum: 3.75

Cu-clad Al-Mg alloy: 3.75

Ordinary PVC: 1.45

Transparent PVC: 1.25

PP: 0.9 10

Low density polyethylene: 0.935

High density polyethylene: 0.935

Eva: 0.935

Color masterbatch: 0.935

Nucleating agent: 1.5

Single sided aluminum foil: 2.0

Double-sided aluminum foil: 2.2

Single-sided hot-melt aluminum foil: 2.24

Cotton paper: 0.75

Cotton yarn (single count): 0.053kg/km

PET film: 1.35

Copper wire (0.14bc): 0.15kg/km.

PP rope: 0.9

PVC rubber strip: 1.45