(20 14? A model in Sihong county) Xiaoming measured the weight of an object with a spring dynamometer and then submerged it in water. Two spring dynamometer readings are shown in the figure, and then

(20 14? A model in Sihong county) Xiaoming measured the weight of an object with a spring dynamometer and then submerged it in water. Two spring dynamometer readings are shown in the figure, and then the object (1) As can be seen from the figure, G=F=4N, F'= 3N,

∴ buoyancy of objects;

f float = g-f ' = 4n-3n = 1n；

(2)∵F float = ρ water v row g= 1N, the object is submerged in water,

∴ the volume of the object:

V=V row =F floating ρ water G =1N/kloc-0 /×103kg/m3×10n/kg =/kloc-0 /×10-4m3,

∫G = mg = 4N。

∴ The mass of the object:

m=Gg=4N 10N/kg=0.4kg，

Density of the object:

ρ=mV=0.4kg 1× 10？ 4m3=4× 103kg/m3。

So the answer is:1; 1× 10-4 m3； 4× 103.